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The Mn3+ ion is unstable in solution and undergoes disproportionation to give Mn2+, MnO2, and H+ ion. Write a balanced ionic equation for the reaction.

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प्रश्न

The Mn3+ ion is unstable in solution and undergoes disproportionation to give Mn2+, MnO2, and H+ ion. Write a balanced ionic equation for the reaction.

दीर्घउत्तर
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उत्तर

The given reaction can be represented as:

\[\ce{Mn^{(3+)}_{(aq)} -> Mn^{(2+)}_{(aq)} + MnO_{2(s)} + H+_{(aq)}}\]

The oxidation half-equation is:

\[\ce{^{+3}Mn^{3+}_{(aq)} -> ^{+4}MnO_{2(s)}}\]

The oxidation number is balanced by adding one electron as:

\[\ce{Mn^{3+}_{(aq)} -> MnO_{2(s)} + e-}\]

The charge is balanced by adding 4H+ ions as:

\[\ce{Mn^{3+}_{(aq)} -> MnO_{2(s)} + 4H_{(aq)}^ + e-}\]

The O atoms and H+ ions are balanced by adding 2H2O molecules as:

\[\ce{Mn^{3+}_{(aq)} + 2H2O_{(l)} -> MnO_{2(s)} + 4H+_{(aq)} + e-}\]    .....(i)

The reduction half equation is:

\[\ce{Mn^{3+}_{(aq)} -> Mn^{2+}_{(aq)}}\]

The oxidation number is balanced by adding one electron as:

\[\ce{Mn^{3+}_{(aq)} + e- -> Mn^{2+}_{(aq)}}\]  ....(ii)

The balanced chemical equation can be obtained by adding equation (i) and (ii) as:

\[\ce{2Mn^{3+}_{(aq)} + 2H_2O_{(l)} -> MnO_{2(s)} + 2Mn^{2+}_{(aq)} + 4H+_{(aq)}}\]

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अध्याय 7: Redox Reactions - EXERCISES [पृष्ठ २८२]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 7 Redox Reactions
EXERCISES | Q 8.21 | पृष्ठ २८२

संबंधित प्रश्न

Consider the reaction:

\[\ce{O3(g) + H2O2(l) → H2O(l) + 2O2(g)}\]

Why it is more appropriate to write these reaction as:

\[\ce{O3(g) + H2O2 (l) → H2O(l) + O2(g) + O2(g)}\]

Also, suggest a technique to investigate the path of the redox reactions.


Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.


Balance the following redox reactions by ion-electron method:

  1. \[\ce{MnO-_4 (aq) + I– (aq) → MnO2 (s) + I2(s) (in basic medium)}\]
  2. \[\ce{MnO-_4 (aq) + SO2 (g) → Mn^{2+} (aq) + HSO-_4  (aq) (in acidic solution)}\]
  3. \[\ce{H2O2 (aq) + Fe^{2+} (aq) → Fe^{3+} (aq) + H2O (l) (in acidic solution)}\]
  4. \[\ce{Cr_2O^{2-}_7 + SO2(g) → Cr^{3+} (aq) + SO^{2-}_4 (aq) (in acidic solution)}\]

Choose the correct option.

For the following redox reactions, find the correct statement.

\[\ce{Sn^{2⊕} + 2Fe^{3⊕}->Sn^{4⊕} + 2Fe^{2⊕}}\]


Justify that the following reaction is redox reaction; identify the species oxidized/reduced, which acts as an oxidant and which acts as a reductant.

\[\ce{2Cu2O_{(S)} + Cu2S_{(S)}->6Cu_{(S)} + SO2_{(g)}}\]


Balance the following reaction by oxidation number method.

\[\ce{Bi(OH)_{3(s)} + Sn(OH)^-_{3(aq)}->Bi_{(s)}  + Sn(OH)^2-_{6(aq)}(basic)}\]


Which of the following is a redox reaction?


Identify the oxidising agent in the following reaction:

\[\ce{CH4_{(g)} + 2O2_{(g)} -> CO2_{(g)} + 2H2O_{(l)}}\]


When methane is burnt completely, oxidation state of carbon changes from ______.


Write balanced chemical equation for the following reactions:

Dichlorine heptaoxide \[\ce{(Cl2O7)}\] in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion \[\ce{(ClO^{-}2)}\] and oxygen gas. (Balance by ion-electron method)


Balance the following equations by the oxidation number method.

\[\ce{I2 + S2O^{2-}3 -> I- + S4O^{2-}6}\]


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\[\ce{HgCl2 (aq) + 2KI (aq) -> HgI2 (s) + 2KCl (aq)}\]


Balance the following ionic equations.

\[\ce{Cr2O^{2-}7 + Fe^{2+} + H+ -> Cr^{3+} + Fe^{3+} + H2O}\]


In \[\ce{Cu^{2+} + Ag -> Cu + Ag^+}\], oxidation half-reaction is:


\[\ce{H2O2 -> 2H^+ + O2 + 2e^-}\]; E0 = −0.68 V.

This equation represents which of the following behaviour of H2O2?


On balancing the given redox reaction,

\[\ce{aCr2O7^2- + Bso3^2- (aq) + CH+ (aq) -> 2aCr^3+ (aq) + bSO4^2- (aq) + c(H2O(1)/2}\]

the coefficients a, b and c are found to be, respectively:


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