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प्रश्न
The line through the points (– 2, a) and (9, 3) has slope `-1/2` Find the value of a.
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उत्तर
The given points are (– 2, a) and (9, 3)
Slope of a line = `(y_2 -y_1)/(x_2 - x_1)`
`-1/2 =(3 - "a")/(9 + 2)`
⇒ `-1/2 = (3 -"a")/11`
2(3 – a) = – 11
⇒ 6 – 2a = – 11
– 2a = – 11 – 6
⇒ – 2a = – 17
⇒ a = `(-17)/(-2)`
∴ The value of a = `17/2`
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