Advertisements
Advertisements
प्रश्न
If the three points (3, – 1), (a, 3) and (1, – 3) are collinear, find the value of a
Advertisements
उत्तर
The vertices are A(3, – 1), B(a, 3) and C(1, – 3)
Slope of a line = `(y_2 - y_1)/(x_2 - x_1)`
Slope of AB = `(3 + 1)/("a" - 3) = 4/("a" - 3)`
Slope of BC = `(3 + 3)/("a" - 1) = 6/("a" - 1)`
Since the three points are collinear.
Slope of AB = Slope BC
`4/("a" - 3) = 6/("a" - 1)`
6(a – 3) = 4(a – 1)
6a – 18 = 4a – 4
6a – 4a = – 4 + 18
2a = 14
⇒ a = `14/2` = 7
The value of a = 7
APPEARS IN
संबंधित प्रश्न
What is the slope of a line whose inclination with positive direction of x-axis is 0°
What is the inclination of a line whose slope is 0
What is the inclination of a line whose slope is 1
Show that the given points are collinear: (– 3, – 4), (7, 2) and (12, 5)
The line through the points (– 2, a) and (9, 3) has slope `-1/2` Find the value of a.
If the points A(2, 2), B(– 2, – 3), C(1, – 3) and D(x, y) form a parallelogram then find the value of x and y.
A quadrilateral has vertices at A(– 4, – 2), B(5, – 1), C(6, 5) and D(– 7, 6). Show that the mid-points of its sides form a parallelogram.
The slope of the line joining (12, 3), (4, a) is `1/8`. The value of ‘a’ is
The slope of the line which is perpendicular to a line joining the points (0, 0) and (− 8, 8) is
If slope of the line PQ is `1/sqrt(3)` then slope of the perpendicular bisector of PQ is
