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The line joining the points (2, 1) and (5, −8) is trisected at the points P and Q. If point P lies on the line 2x − y + k = 0. Find the value of k. - Mathematics

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प्रश्न

The line joining the points (2, 1) and (5, −8) is trisected at the points P and Q. If point P lies on the line 2x − y + k = 0. Find the value of k.

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उत्तर

Key concept: Section formula

`(x,y) = (mx_2 +nx_1)/(m+n), (my_2 + ny_1)/(m+n)`

`p(x,y) = (1(5)+2(2))/(1+2), (1(-8)+2(1))/(1+2)`

`x = (5+4)/3`

`x=9/3`

x = 3

`y = (-8+2)/3`

`y = (-6)/3`

y = −2

2x − y + k = 0     (x = 3, y = −2)

2(3) − (−2) + k = 0

6 + 2 + k = 0

k = −8

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अध्याय 6: Co-Ordinate Geometry - Exercise 6.3 [पृष्ठ ३१]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 6 Co-Ordinate Geometry
Exercise 6.3 | Q 53 | पृष्ठ ३१

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