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प्रश्न
The distance of the point P (4, 3) from the origin is
विकल्प
4
3
5
7
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उत्तर
The point P(4,3) is shown in the graph given below:
In ΔOAPis right angled triangle where
OA = 4
and AP =3
By using Pythagoras theorem:
`OP = sqrt(OA^2 + AP^2)`
` = sqrt(4^2 +3^2)`
`=sqrt(16 +9)`
`=sqrt25`
`=5`
Thus the distance of the point P(4,3) from the origin is 5.
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Find the value of a, so that the point ( 3,a ) lies on the line represented by 2x - 3y =5 .
In what ratio does the point C (4,5) divides the join of A (2,3) and B (7,8) ?
Find the value of k, if the points A(7, −2), B (5, 1) and C (3, 2k) are collinear.
If P (2, p) is the mid-point of the line segment joining the points A (6, −5) and B (−2, 11). find the value of p.
What is the distance between the points \[A\left( \sin\theta - \cos\theta, 0 \right)\] and \[B\left( 0, \sin\theta + \cos\theta \right)\] ?
Write the equations of the x-axis and y-axis.
Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).
If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.
Given points are P(1, 2), Q(0, 0) and R(x, y).
The given points are collinear, so the area of the triangle formed by them is `square`.
∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`
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Hence, the relation between x and y is `square`.
