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प्रश्न
The line 4x + 3y – 12 = 0 cuts the coordinate axes at A and B. The area of ΔOAB is ______.
रिक्त स्थान भरें
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उत्तर
The line 4x + 3y – 12 = 0 cuts the coordinate axes at A and B. The area of ΔOAB is 6 sq. units.
Explanation:
x-intercept (A): set y = 0
⇒ 4x – 12 = 0
⇒ x = 3
So A(3, 0).
y-intercept (B): set x = 0
⇒ 3y – 12 = 0
⇒ y = 4
So B(0, 4).
Triangle OAB is right with legs 3 and 4, so area = `1/2 xx 3 xx 4` = 6 square units.
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