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The length of time (in minutes) that a certain person speaks on the telephone is found to be random phenomenon, with a probability function specified by the probability density

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प्रश्न

The length of time (in minutes) that a certain person speaks on the telephone is found to be random phenomenon, with a probability function specified by the probability density function f(x) as 
f(x) = `{{:("Ae"^((-x)/5)",",  "for"  x ≥ 0),(0",",  "otherwise"):}`
What is the probability that the number of minutes that person will talk over the phone is (i) more than 10 minutes, (ii) less than 5 minutes and (iii) between 5 and 10 minutes

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उत्तर

(i) more than 10 minutes

`int_10^00 "f"(x)  "d"x`

= `1/5 int_10^oo "e"^(x/5)  "d"x`

= `1/5 ("e"^((-x)/5)/(((-1)/5)))^oo`

= `- ["e"^((-x)/5)]_10^oo`

= `- ["e"^-oo - "e"^((-10)/5)]`

= `- [0 - "e"^-2]`

= `"e"^-2`

= `1/"e"^2`

(ii) less than 5 minutes

`int_0^5 f(x)  "d"x = int_0^5 "Ae"^((x)/5)`

= `1/5 int_0^5 "e"^((-x)/5)  "d"x`

= `1/5 ["e"^((-x)/5)/((-1)/5)]_0^5`

= `- ["e"^((-x)/5)]_0^5`

= `- ["e"^((-5)/5) - "e"^0]`

= `- ("e"^-1 - 1)`

= `1 - "e"^-1`

= `1 - 1/"e"`

= `("e" - 1)/"e"`

(iii) between 5 and 10 minutes

`int__5^10 "f"(x)  "d"x = int_5^10 "Ae"^((-x)/5)  "d"x`

= `int_5^10 1/5 "e"^((-x)/5)  "d"x`

= `1/5 ["e"^((-x)/5)/((-1)/5)]_5^10`

= `- ["e"^((-x)/5)]_5^10`

= `- ["e"^((-10)/5) - "e"^((-5)/5)]`

= `[-"e"^-2 - "e"^-1]`

= `"e"^-1 - "e"^-2`

= `1/"e"- 1/"e"^2`

= `("e" - 1)/"e"^2`

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Random Variable
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Random Variable and Mathematical expectation - Exercise 6.1 [पृष्ठ १३३]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
अध्याय 6 Random Variable and Mathematical expectation
Exercise 6.1 | Q 9. (b) | पृष्ठ १३३

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