Advertisements
Advertisements
प्रश्न
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
Advertisements
उत्तर
Let length and breadth of rectangle be ‘l’ and ‘b’ respectively
Given that length is `1/3` of breadth,
∴ l = `1/3 xx "b"`
⇒ l = `"b"/3`
⇒ b = 3l ...(1)
Also given that perimeter is 64 m
Perimeter = 2 × (l + b)
2 × 1 + 2 × b = 64
Substituting for value of b from (1), we get
2l + 2(3l) = 64
∴ 2l + 6l = 64
8l = 64
∴ l = `64/8` = 8 m
b = 3l
= 3 × 8
= 24 m
Ienglh l = 8 m in and breadth b = 24 m
APPEARS IN
संबंधित प्रश्न
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
(−xy3) × (yx3) × (xy)
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( - \frac{4}{7} a^2 b \right) \times \left( - \frac{2}{3} b^2 c \right) \times \left( - \frac{7}{6} c^2 a \right)\]
Multiply: x + 4 by x − 5
Multiply: abx, −3a2x and 7b2x3
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
Solve: ( -3x2 ) × ( -4xy)
Solve: (-12x) × 3y2
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
–5a2bc, 11ab, 13abc2
