Advertisements
Advertisements
प्रश्न
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
Advertisements
उत्तर
Let length and breadth of rectangle be ‘l’ and ‘b’ respectively
Given that length is `1/3` of breadth,
∴ l = `1/3 xx "b"`
⇒ l = `"b"/3`
⇒ b = 3l ...(1)
Also given that perimeter is 64 m
Perimeter = 2 × (l + b)
2 × 1 + 2 × b = 64
Substituting for value of b from (1), we get
2l + 2(3l) = 64
∴ 2l + 6l = 64
8l = 64
∴ l = `64/8` = 8 m
b = 3l
= 3 × 8
= 24 m
Ienglh l = 8 m in and breadth b = 24 m
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
Multiply: 4a and 6a + 7
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
–7pq2r3, –13p3q2r
Multiply the following:
abc, (bc + ca)
Multiply the following:
6mn, 0mn
