Advertisements
Advertisements
प्रश्न
The income of a man is increased in the ratio of 10 : 11. If the increase in his income is Rs 600 per month, find his new income.
Advertisements
उत्तर
Let the present income = 10x
then increased income = 11x
∴ Increase per month
= 11x - 10x
= x
∴ x = ₹600
Now his new income
= 11x
= 11 x 600
= ₹6600.
APPEARS IN
संबंधित प्रश्न
Find the compounded ratio of the following:
15: 16 and 8 : 5
If x2, 4 and 9 are in continued proportion, find x.
If `a/b = c/d = e/f`, Prove that each of these ratios is equal to `(a + c + e)/(b + d + f)`.
If x : y = 2 : 3 and y : z = 5 : 7, find x : y : z.
An alloy consists of `27(1)/(2)` kg of copper and `2(3)/(4)` kg of tin. Find the ratio by weight of tin to the alloy.
Find two numbers in the ratio of 8 : 7 such that when each is decreased by , they are in the ratio 11 : 9.
The ratio of the number of boys to the number of girls in a school of 560 pupils is 5 : 3. If 10 new boys are admitted, find how many new girls may be admitted so that the ratio of the number of boys to the number of girls may change to 3 : 2.
Mr. Sahai and his wife are both school teachers and earn Rs 16800 and Rs 10500 per month respectively. Find the ratio of
(i) Mr. Sahai's income to his wife's income;
(ii) Mrs. Sahai's income to her husband's income;
(iii) Mr. Sahai's income to the total income of the two.
Choose the correct answer from the given options :
The ratio of 45 minutes to `5(3)/(4)` hours is
Given below is a Mathematical term.
Find the ratio of consonants to vowels in the term.
