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प्रश्न
The force of attraction between two unit point masses separated by a unit distance is called
विकल्प
gravitational potential
acceleration due to gravity
gravitational field
universal gravitational constant
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उत्तर
universal gravitational constant
Explanation:
F = `"G"("m"_1"m"_2)/"d"^2`
F = G, i.e., the force of attraction between two unit point masses separated by a unit distance is a universal gravitational constant.
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संबंधित प्रश्न
Fill in the following blank with suitable word :
The value of g on the earth is about………………. of that on the moon.
The mass of the moon is `1/81` of the mass of the earth. Its diameter is `1/3.7` of that of the earth. If acceleration due to gravity on the surface of the earth is 9.8 m/s2, then the acceleration due to gravity on the surface of the moon.
The depth 'd' below the surface of the earth at which acceleration due to gravity becomes `(g/n)` is ______.
R = radius of the earth, 'g' = acceleration due to gravity, n = integer
When the value of acceleration due to gravity 'g' becomes `(g/3)` above the earth's surface at height 'h' then relation between 'h' and 'R' is ______.
R =radius of the earth
Suppose the gravity of the earth suddenly becomes zero, then in which direction will the moon begin to move if no other celestial body affects it?
Write if the following statement is correct or wrong.
The value of g is the same everywhere on the surface of the earth.
The moon has a mass of 1/81 that of the earth and a radius of 1/4 that of the earth. The escape speed from the surface of the earth is 11.2 km/s. The escape speed from the surface of the moon is ______.
A lift of mass 'm' is connected to a rope which is moving upward with maximum acceleration 'a'. For maximum safe stress, the elastic limit of the rope is 'T'. The minimum diameter of the rope is ______.
(g = gravitational acceleration)
If the Moon's mass is 1/80 of Earth's mass and its radius is 1/4 of Earth's radius, what is the ratio of g on the Moon to g on Earth?
Which formula correctly represents the acceleration due to gravity at Earth's surface?
