Advertisements
Advertisements
प्रश्न
The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.
(i) 3s1
(ii) 3d14s2
(iii) 3d24s2
(iv) 3s23p3
Advertisements
उत्तर
(iii) 3d24s2
(iv) 3s23p3
Explanation:
Elements which have only s-electron in the valence shell do not show more than one oxidation state. Thus, element with 3s1 as outer electronic configuration shows only one oxidation state of +1.
Transition elements, i.e., elements (ii, iii) having incompletely filled orbitals in the penultimate shell show variable oxidation states. Thus, element with outer electronic configuration as 3d1 4s2 shows variable oxidation states of +2 and +3 and the element with outer electronic configuration as 3d24s2 shows variable oxidation states of +2, +3 and +4.
p-Block elements also show variable oxidation states due to a number of reasons such as involvement of J-orbitals and inert pair effect. For example, element (iv) with 3s2 3p3 as (i.e., P) as the outer electronic configuration shows variable oxidation states of +3 and +5 due to involvement of d-orbitals.
APPEARS IN
संबंधित प्रश्न
Assign oxidation numbers to the underlined element in the following species:
H4P2O7
Assign oxidation numbers to the underlined elements in the following species:
NaBH4
Assign oxidation numbers to the underlined elements in the following species:
H2S2O7
Assign oxidation numbers to the underlined elements in the following species:
KAl(SO4)2.12 H2O
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
H2S4O6
What is the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
Fe3O4
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
CH3CH2OH
Consider the elements: Cs, Ne, I and F.
Identify the element that exhibits only postive oxidation state.
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
Calculate the oxidation number of phosphorus in the following species.
\[\ce{HPO^{2-}3}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2S2O3}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO3}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO4}\]
The oxidation number of P in Mg2P207 is ____________.
The oxidation number and covalency of sulphur in sulphur molecules (Sg) are:
In which of the following species oxidation number of the element(s) is equal to + 4?
In which of the following species, the oxidation number of the atom of the underlined elements is/are equal to +1?
Oxidation state of sulphur in anions `"SO"_3^(2-)`, `"S"_2"O"_4^(2-)` and `"S"_2"O"_6^(2-)` increases in the orders:
