Advertisements
Advertisements
प्रश्न
The equation of directrix of the parabola y2 = -x is:
विकल्प
4x + 1 = 0
4x - 1 = 0
x – 1 = 0
x + 4 = 0
Advertisements
उत्तर
4x - 1 = 0
APPEARS IN
संबंधित प्रश्न
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = - 16y
The focus of the parabola x2 = 16y is:
Find the equation of the ellipse in the cases given below:
Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis
Find the equation of the hyperbola in the cases given below:
Foci (± 2, 0), Eccentricity = `3/2`
Find the equation of the hyperbola in the cases given below:
Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4
Find the equation of the hyperbola in the cases given below:
Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 3)^2/225 + (y - 4)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(y - 2)^3/25 + (x + 1)^2/16` = 1
Choose the correct alternative:
If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14
If the eccentricity e > 1, the conic section is:
