Advertisements
Advertisements
प्रश्न
The energy of hydrogen atom in an orbit is −1.51 eV. What are the kinetic and potential energies of the electron in this orbit?
Advertisements
उत्तर
Total energy = −1.51 eV
So, Potential energy = 2 × Total energy = −3.02 eV
Kinetic energy = −Total energy = 1.51 eV
APPEARS IN
संबंधित प्रश्न
Write two important limitations of Rutherford's nuclear model of the atom.
In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 75, when a α-particle of 5 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?
The total energy of an electron in the ground state of the hydrogen atom is -13·6 eV. Its total energy, when a hydrogen atom is in the first excited state, is ______.
The first line of Balmer series (Hα) in the spectrum of hydrogen is obtained when an electron of hydrogen atom goes from ______.
For 7.7 Mev alpha particles scattering from aluminium (Z = 13), the distance of closest approach in a bead on collision is ______.
Useful data
`1/(4 pi ∈_0) = 8.99 xx 10^9` newton m2C-2; c = 1.60 × 10-19 C; leV = 1.60 × 10-19j.
The ratio active Nude 7N13 decays 6C13 through the emission of
In 88 Ra226 nucleus, there are
The ratio of minimum to maxm wavelength in ballmer series is:-
Draw a graph showing the variation of the number of particles scattered (N) with the scattering angle θ in the Geiger-Marsden experiment. Why only a small fraction of the particles are scattered at θ > 90°?
How is the size of a nucleus found experimentally? Write the relation between the radius and mass number of a nucleus.
