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प्रश्न
The energy of an atom (or ion) in its ground state is −54.4 eV. It may be
विकल्प
hydrogen
deuterium
He+
Li++
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उत्तर
He+
The total energy of a hydrogen-like ion, having Z protons in its nucleus, is given by
`E = - (13.6Z^2)/(n^2)eV`
Here, n = Principal quantum number
For ground state,
n = 1
∴ Total energy, E = - `13.6 Z^2 eV`
For hydrogen,
Z = 1
∴ Total energy, E = - 13.6 eV
For deuterium,
Z = 1
∴ Total energy, E = - 13.6 eV
For He+,
Z = 2
∴ Total energy, E = - 13.6×22 = - 54.4 eV
For Li++,
Z = 3
∴ Total energy, E = - 13.6×32 = - 122.4 eV
Hence, the ion having an energy of −54.4 eV in its ground state may be He+.
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