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The Eccentricity of the Ellipse 4x2 + 9y2 = 36 is - Mathematics

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प्रश्न

The eccentricity of the ellipse 4x2 + 9y2 = 36 is

विकल्प

  • \[\frac{1}{2\sqrt{3}}\]

     

  • \[\frac{1}{\sqrt{3}}\]

     

  • \[\frac{\sqrt{5}}{3}\]

     

  • \[\frac{\sqrt{5}}{6}\]

     

MCQ
योग
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उत्तर

\[\frac{\sqrt{5}}{3}\]
\[4 x^2 + 9 y^2 = 36\]
\[ \Rightarrow \frac{x^2}{9} + \frac{y^2}{4} = 1\]
\[\text{ Comparing it with }\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, \text{ we get: }\]
\[a = 3\text{ and }b = 2\]
Here, a > b, so the major and the minor axes of the ellipse are along the x - axis and y - axis, respectively.
\[\text{ Now }, e = \sqrt{1 - \frac{b^2}{a^2}}\]
\[ \Rightarrow e = \sqrt{1 - \frac{4}{9}}\]
\[ \Rightarrow e = \sqrt{\frac{5}{9}}\]
\[ \Rightarrow e = \frac{\sqrt{5}}{3}\]

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Introduction of Ellipse
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 26: Ellipse - Exercise 26.3 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 26 Ellipse
Exercise 26.3 | Q 12 | पृष्ठ २८
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