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प्रश्न
The diagram given below shows a displacement distance graph of a wave. If the velocity of wave is 160 ms-1, calculate:
- wavelength
- frequency
- amplitude.
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उत्तर
(i) Wavelength (λ) = Distance between two consecutive crests
= 1.0 - 0.2 = 0.8 m
(ii) Frequency (f) = `"v"/lambda`
Wavelength (v) = 160ms-1 ...(given)
∴ f = `160/0.8 = 200` Hz
(iii) Amplitude = Maximum displacement from mean position = 10 cm
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