हिंदी

The curved surface area of a frustum of a cone is πl (r1 + r2), where l=h2+(r1+r2)2, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height. - Mathematics

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प्रश्न

The curved surface area of a frustum of a cone is πl (r1 + r2), where `l = sqrt(h^2 + (r_1 + r_2)^2)`, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
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उत्तर

This statement is False.

Explanation:

We know that,

Curved surface area of frustum = πl(r1 + r2)

Where r1 and r2 are the radii of two ends (r1 > r2)

And l = slant height

`l = sqrt(h^2 + (r_1 + r_2)^2)`   ...[In the statement, formula for calculating slant height is incorrect]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Surface Areas and Volumes - Exercise 12.2 [पृष्ठ १४३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 12 Surface Areas and Volumes
Exercise 12.2 | Q 7 | पृष्ठ १४३
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