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प्रश्न
The correct order of increasing reactivity of C-X bond towards nucleophile in the following compounds is:
(I)
(II)
(III) (CH3)3 C-X
(IV) (CH3)2 CH-X
विकल्प
I < II < III < IV
II < I < III < IV
III < IV < II < I
IV < III < I < II
I < II < IV < III
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उत्तर
I < II < IV < III
Explanation:
Alkyl halides are more reactive than aryl halides. This is because of the partial double bond character between the benzene ring and the halogen. Further, in alkyl halides, the greater the stability of carbocation formed, the more would be the reactivity. Thus, the tertiary halide is more reactive. Nitro group which is electron-withdrawing increases the reactivity of aryl halide.
Notes
The correct option is not given in the textbook.
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संबंधित प्रश्न
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(I)
\[\begin{array}{cc}
\ce{CH3-CH-C2H5}\\
|\\
\ce{Cl}\end{array}\]
(II)
(III)
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\[\begin{array}{cc}
\ce{\phantom{.......}CH3}\\
\phantom{.....}|\\
\ce{CH3-CH}\\
\phantom{.....}|\\
\ce{\phantom{..........}CH2Cl}
\end{array}\]
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| \[\begin{array}{cc} \ce{CH3CH - CH3}\\ |\phantom{.....}\\ \ce{X\phantom{.....}} \end{array}\] |
vinyl halide |
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| \[\ce{CH2 = CH - X}\] | allyl halide |
| benzyl halide | |
| aryl halide |
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry either] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}
\end{array}\]
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