Advertisements
Advertisements
प्रश्न
The base of the cylindrical vessel measures 300 cm2. Water is poured into it up to a depth of 6 cm. Calculate the pressure of water on the base in the vessel.
Advertisements
उत्तर
Area of base of cylinder = A = 300 cm2
A = 300 × 10 m2
A = 3 × 102 m2
Height (or depth) of water column = h = 6 cm
h = `6/100` m
Density of water = ρ = 1000 kg/m3
Acceleration due to gravity = g = 10 m/s2
Pressure at the base in vessel = P = hρg
ρ = `6/100xx1000xx10`
P = 600 Pa
APPEARS IN
संबंधित प्रश्न
The weight of a body floating in a liquid is ........
Define buoyant force. Name two factors on which buoyant force depends.
A piece of wood floats on water. The buoyant force on wood will be
The density of brass is 8.4 g cm-3. What do you mean by this statement?
A dam has broader walls at the bottom than at the top. Explain.
Complete the following sentence :
Pressure at all points at the same depth is ....................
Describe an experiment to show that a body immersed in a liquid appears lighter than it really is.
The point at which the force of buoyancy is supposed to act is known as ______.
In a fluid, buoyant force exists because the pressure at the ______ of an object is greater than the pressure at the top.
What do you understand by the term “Buoyancy”.
