Advertisements
Advertisements
प्रश्न
Sum of a – b + ab, b + c – bc and c – a – ac is ______.
विकल्प
2c + ab – ac – bc
2c – ab – ac – bc
2c + ab + ac + bc
2c – ab + ac + bc
Advertisements
उत्तर
Sum of a – b + ab, b + c – bc and c – a – ac is 2c + ab – ac – bc.
Explanation:
Required sum = (a – b + ab) + (b + c – bc) + (c – a – ac)
= a – b + ab + b + c – bc + c – a – ac
= 2c + ab – ac – bc ...[Adding the like terms and retaining others]
APPEARS IN
संबंधित प्रश्न
Take away:
\[\frac{5 a^2}{2} + \frac{3 a^3}{2} + \frac{a}{3} - \frac{6}{5} \text { from } \frac{1}{3} a^3 - \frac{3}{4} a^2 - \frac{5}{2}\]
Take away:
\[\frac{7}{4} x^3 + \frac{3}{5} x^2 + \frac{1}{2}x + \frac{9}{2}\text { from } \frac{7}{2} - \frac{x}{3} - \frac{x^2}{5}\]
Simplify the following:
[5 − 3x + 2y − (2x − y)] − (3x − 7y + 9)
Simplify the following:
\[\frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
Identify the like terms: 12x3y2z, – y3x2z, 4z3y2x, 6x3z2y, – 5y3x2z
Which of the following are like terms?
Which of the following is a pair of like terms?
–5a2b and –5b2a are ______ terms.
Which set contains unlike terms?
