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प्रश्न
Subtract the second expression from the first:
a3 - 1 + a, 3a - 2a2
योग
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उत्तर
(a3 - 1 + a) - (3a - 2a2)
= a3 - 1 + a - 3a + 2a2
= a3 + 2a2 - 2a - 1
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