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प्रश्न
Find the sum of:
9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 4bx – 3
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उत्तर
9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 4bx – 3
9ax – 6bx + 8 + 4ax + 8bx – 7 – 6ax – 4bx – 3
= 9ax + 4ax – 6ax – 6bx + 8bx – 4bx + 8 – 7 – 3
= 13ax – 6ax + 8bx – 10bx + 8 – 10
= 7ax – 2bx – 2
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संबंधित प्रश्न
Write numerical co-efficient of the following: – 9a2b3
In -5x3y2z4 ; write the coefficient of yz2. Also, write the degree of the given algebraic expression.
Add : - 9x, 3x and 4x
Add : - 3a + 2b and 3a + b
Enclose the given term in bracket as required:
x – y – z = x - {…….)
Simplify: 9a (2b – 3a + 7c)
Simplify: 8 (2a + 3b – c) – 10 (a + 2b + 3c)
Simplify: `8"x" - ["4y" - {"4x" + ("2x" - bar"2y - 2x")}]`
Factorise the following expression.
2a3 – 3a2b + 5ab2 – ab
Find the numerical coefficient of the terms:
10xyz, –7xy2z, –9xyz, 2xy2z, 2x2y2z2
