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प्रश्न
Find the sum of:
9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 4bx – 3
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उत्तर
9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 4bx – 3
9ax – 6bx + 8 + 4ax + 8bx – 7 – 6ax – 4bx – 3
= 9ax + 4ax – 6ax – 6bx + 8bx – 4bx + 8 – 7 – 3
= 13ax – 6ax + 8bx – 10bx + 8 – 10
= 7ax – 2bx – 2
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संबंधित प्रश्न
Constant is only 8 other is variable 12 – 5 z – 4
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Simplify: 8 (2a + 3b – c) – 10 (a + 2b + 3c)
Simplify: 2 [a – 3 {a + 5 {a – 2) + 7}]
Find the numerical co-efficient of the following term:
121bc
The value of (2x2 + 4) ÷ 2 is ______.
The coefficient in – 37abc is ______.
Identify term which contain x and give the coefficient of x.
1 + x + xy
Identify term which contain x and give the coefficient of x.
7x + xy2
Factors of –5x2y2z are ______.
