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State Gauss’ Law. - Physics (Theory)

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प्रश्न

State Gauss’ Law.

Answer the following question briefly and to the point:

State Gauss’ theorem.

संक्षेप में उत्तर
नियम
प्रमेय
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उत्तर १

The electric flux (ΦE) through any closed surface is equal to `1/in_0` times the ‘net’ change q enclosed by the surface.

ΦE = `oint  vec E d vec A`

= `q/in_0`

0 = Permittivity of free space.

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उत्तर २

Gauss’ theorem states that the net electric flux over a closed surface is `1/epsilon_0` times the net electric charge enclosed by the surface.

Φ = `oint vec E * d vec A` 

= `q/epsilon_0`

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2015-2016 (March) Set 1

संबंधित प्रश्न

A point charge of 2.0 μC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?


Electric intensity outside a charged cylinder having the charge per unit length 'λ' at a distance from its axis is ________.

(a) E = `(2pi in_0 lambda)/(Kr^2)`

(b) E = `(in_0 lambda)/(2piKr^2)`

(c) E = `lambda/(2piin_0Kr)`

(d) E = `(4piin_0lambda)/(Kr^2)`


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Draw a graph to show the variation of E with perpendicular distance r from the line of charge.


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Which statement is true for Gauss law -


Consider a sphere of radius R with charge density distributed as

ρ(r)  = kr for r ≤ R

        = 0 for r > R

  1. Find the electric field at all points r.
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  1. Obtain the expression for the electric field intensity due to a uniformly charged spherical shell of radius R at a point distant r from the centre of the shell outside it.
  2. Draw a graph showing the variation of electric field intensity E with r, for r > R and r < R.

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