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प्रश्न
State Einstein photoelectric equation.
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उत्तर
K.E.max = `(hν - phi_0)`
or K.E.max = (hν – hv0)
or `1/2 mv_(max)^2 = hv - hv_0`
where, (K.E.)max → Maximum kinetic energy
= `1/2 mv_(max)^2`
`phi_0` → Photoelectric work function = hv0
h → Planck’s constant
v → Frequency of radiation
v0 → Threshold frequency
संबंधित प्रश्न
Photocurrent recorded in the microammeter in an experimental setup of the photoelectric effect vanishes when the retarding potential is more than 0.8 V if the wavelength of incident radiation is 4950 Å. If the source of incident radiation is changed, the stopping potential turns out to be 1.2 V. Find the work function of the cathode material and the wavelength of the second source.
The minimum frequency for photoelectric effect on metal is 7 × 1014 Hz, Find the work function of the metal.
Find the kinetic energy of the emitted electron, if in photoelectric effect energy of incident Photon is 4 eV and work function is 2.4 eV.
The energy of the incident photon on the metal surface is 3 W and then 5 W, where W is the work function for that metal. The ratio of velocities of emitted photoelectrons is ______.
The following graph shows the stopping potential V0 versus frequency v for photoelectric emission from two metals A and B. The slope of each of the lines gives ______
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When light falls on a metal surface, the maximum kinetic energy of the emitted photoelectrons depends upon ______
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According to Einstein's photoelectric equation, the graph of kinetic energy of the photoelectron emitted from the metal versus the frequency of incident radiation gives a straight line graph whose slopе ______.
