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प्रश्न
Calculate the stopping potential when the metal with the work function 0.6 eV is illuminated with the light of 2 eV.
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उत्तर
Given: φ0 = 0.6 eV, E = 2 eV
To find: Stopping potential (V0)
Formula: V0 = `("E" - phi_0)/"e"`
Calculation:
V0 = `(2 xx 1.6 xx 10^-19 - 0.6 xx 1.6 xx 10^-1)/(1.6 xx 10^-19)`
= 2 - 0.6
= 1.4 V
The stopping potential is 1.4 V.
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