हिंदी

Solve for X : Cos ( Tan − 1 X ) = Sin ( Cot − 1 3 4 ) . - Mathematics

Advertisements
Advertisements

प्रश्न

Solve for x : \[\cos \left( \tan^{- 1} x \right) = \sin \left( \cot^{- 1} \frac{3}{4} \right)\] .

Advertisements

उत्तर

Given: 

\[\cos \left( \tan^{- 1} x \right) = \sin \left( \cot^{- 1} \frac{3}{4} \right)\]      .........(1)

\[cos\theta = \sin\left( \frac{\pi}{2} - \theta \right)\]

\[ \Rightarrow \cos\left( \tan^{- 1} x \right) = \sin\left( \frac{\pi}{2} - \tan^{- 1} x \right)\]

\[ \Rightarrow \cos\left( \tan^{- 1} x \right) = \sin\left( \cot^{- 1} x \right)\]

Substituting the value of 

\[\cos\left( \tan^{- 1} x \right)\]  in equation (1), we get:

\[\sin\left( \cot^{- 1} x \right) = \sin\left( \cot^{- 1} \frac{3}{4} \right)\]

\[ \Rightarrow x = \frac{3}{4}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (March) Foreign Set 1

संबंधित प्रश्न

 

If `sin (sin^(−1)(1/5)+cos^(−1) x)=1`, then find the value of x.

 

Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


Write the function in the simplest form:  `tan^(-1)  ((cos x - sin x)/(cos x + sin x)) `,` 0 < x < pi`


Find the value of `cot(tan^(-1) a + cot^(-1) a)`


Find the value of the given expression.

`tan(sin^(-1)  3/5 + cot^(-1)  3/2)`


Prove that:

`cos^(-1)  4/5 + cos^(-1)  12/13 = cos^(-1)  33/65`


Prove `tan^(-1)   1/5 + tan^(-1)  (1/7) + tan^(-1)  1/3 + tan^(-1)  1/8 = pi/4`


Solve for x : \[\tan^{- 1} \left( \frac{x - 2}{x - 1} \right) + \tan^{- 1} \left( \frac{x + 2}{x + 1} \right) = \frac{\pi}{4}\] .


Prove that

\[2 \tan^{- 1} \left( \frac{1}{5} \right) + \sec^{- 1} \left( \frac{5\sqrt{2}}{7} \right) + 2 \tan^{- 1} \left( \frac{1}{8} \right) = \frac{\pi}{4}\] .

 

Solve: tan-1 4 x + tan-1 6x `= π/(4)`.


Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 (cos pi)`


Find the value, if it exists. If not, give the reason for non-existence

`tan^-1(sin(- (5pi)/2))`


Find the value of `cot[sin^-1  3/5 + sin^-1  4/5]`


Prove that `tan^-1x + tan^-1y + tan^-1z = tan^-1[(x + y + z - xyz)/(1 - xy - yz - zx)]`


Prove that `tan^-1x + tan^-1  (2x)/(1 - x^2) = tan^-1  (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`


Solve: `tan^-1x = cos^-1  (1 - "a"^2)/(1 + "a"^2) - cos^-1  (1 - "b"^2)/(1 + "b"^2), "a" > 0, "b" > 0`


Solve: `2tan^-1 (cos x) = tan^-1 (2"cosec"  x)`


Solve: `cot^-1 x - cot^-1 (x + 2) = pi/12, x > 0`


Choose the correct alternative:

`tan^-1 (1/4) + tan^-1 (2/9)` is equal to


Choose the correct alternative:

`sin^-1 (tan  pi/4) - sin^-1 (sqrt(3/x)) = pi/6`. Then x is a root of the equation


Choose the correct alternative:

If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to


Evaluate tan (tan–1(– 4)).


Evaluate: `sin^-1 [cos(sin^-1 sqrt(3)/2)]`


Solve for x : `"sin"^-1  2 "x" + sin^-1  3"x" = pi/3`


The value of `"tan"^-1 (3/4) + "tan"^-1 (1/7)` is ____________.


`"cos" (2  "tan"^-1 1/7) - "sin" (4  "sin"^-1 1/3) =` ____________.


If `3  "sin"^-1 ((2"x")/(1 + "x"^2)) - 4  "cos"^-1 ((1 - "x"^2)/(1 + "x"^2)) + 2 "tan"^-1 ((2"x")/(1 - "x"^2)) = pi/3` then x is equal to ____________.


Find the value of `cos^-1 (1/2) + 2sin^-1 (1/2) ->`:-


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×