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प्रश्न
Find the value, if it exists. If not, give the reason for non-existence
`tan^-1(sin(- (5pi)/2))`
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उत्तर
`tan^-1(sin(- (5pi)/2)) = tan^-1[ - sin (5pi)/2]`
= `tan^-1 (- sin(2pi + pi/2))`
= `tan^-1 (- sin pi/2)`
= `tan^-1 (- 1)`
= `- tan^-1 (1)`
= `- pi/4`
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