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Solve ∣ ∣ ∣ X + 1 3 ∣ ∣ ∣ > 8 3 - Mathematics

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प्रश्न

Solve  

\[\left| x + \frac{1}{3} \right| > \frac{8}{3}\] 

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उत्तर

\[\text{ As }, \left| x + \frac{1}{3} \right| > \frac{8}{3}\]
\[ \Rightarrow \left( x + \frac{1}{3} \right) < \frac{- 8}{3} \text{ or } \left( x + \frac{1}{3} \right) > \frac{8}{3} \left( \text{ As }, \left| x \right| > a \Rightarrow x < - a or x > a \right)\]
\[ \Rightarrow x < - \frac{1}{3} - \frac{8}{3} \text{ or } x > \frac{8}{3} - \frac{1}{3}\]
\[ \Rightarrow x < - \frac{9}{3} \text{ or } x > \frac{7}{3}\]
\[ \Rightarrow x < - 3 \text{ or } x > \frac{7}{3}\]
\[ \therefore x \in \left( - \infty , - 3 \right) \cup \left( \frac{7}{3}, \infty \right)\]

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अध्याय 15: Linear Inequations - Exercise 15.3 [पृष्ठ २२]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 15 Linear Inequations
Exercise 15.3 | Q 1 | पृष्ठ २२
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