Question

Solve the following quadratic equation:

6x² + x – 12 = 0

Answer 1

Given: 

6x² + x – 12 = 0 

⇒ 6x² + 9x – 8x – 12 = 0 

⇒ 3x(2x + 3) – 4(2x + 3) = 0 

⇒ (3x – 4)(2x + 3) = 0 

⇒ 3x – 4 = 0 or 2x + 3 = 0 

⇒ `x = 4/3` or `x = (-3)/2` 

Hence, `4/3` and `(-3)/2` are the roots of the equation 6x² + x – 12 = 0.