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प्रश्न
Solve the following quadratic equation:
6x2 + x – 12 = 0
बेरीज
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उत्तर
Given:
6x2 + x – 12 = 0
⇒ 6x2 + 9x – 8x – 12 = 0
⇒ 3x(2x + 3) – 4(2x + 3) = 0
⇒ (3x – 4)(2x + 3) = 0
⇒ 3x – 4 = 0 or 2x + 3 = 0
⇒ `x = 4/3` or `x = (-3)/2`
Hence, `4/3` and `(-3)/2` are the roots of the equation 6x2 + x – 12 = 0.
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