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प्रश्न
Solve the following quadratic equation:
(2x – 3) (3x + 1) = 0
योग
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उत्तर
(2x – 3) (3x + 1) = 0
⇒ 2x – 3 = 0 or 3x + 1 = 0
⇒ 2x = 3 or 3x = –1
⇒ `x = 3/2` or `x = (-1)/3`
Hence, the roots of the given equation are `3/2` and `(-1)/3`.
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