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Solve the following linear programming problem graphically: Minimize: Z = 5x + 10y Subject to constraints: x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x ≥ 0, y ≥ 0. - Mathematics

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प्रश्न

Solve the following linear programming problem graphically:

Minimize: Z = 5x + 10y

Subject to constraints:

x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x ≥ 0, y ≥ 0.

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उत्तर

Here, objective function

Min. Z = 5x + 10y

Subject to constraints

x + 2y ≤ 120,

x + y ≥ 60

x – 2y ≥ 0

x ≥ 0, y ≥ 0

Changing inequations to equations, we get

x + 2y = 120  ...(i)

x 0 120
y 60 0

x + y = 60  ...(ii)

x 0 60
y 60 0

x – 2y = 0  ...(iii)

x 0 120
y 0 60

On solving equations (i) and (ii), we get point of intersection E(0, 60).

On solving equations (ii) and (iii), we get point of intersection C(40, 20).

On solving equations (i) and (iii), we get point of intersection B(60, 30).

Corner Points Z = 5x + 10y
A(120, 0) Z = 5 × 120 + 10 × 0 = 600
B(60, 30) Z = 5 × 60 + 10 × 30 = 300 + 300 = 600
C(40, 20) Z = 5 × 40 + 10 × 20 = 200 + 200 = 400
D(60, 0) Z = 5 × 60 + 0 × 0 = 300 `rightarrow` Min.

Hence, min. value Z is 300, when x = 60 and y = 0.

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