Advertisements
Advertisements
प्रश्न
Solve the following equation by trial and error method:
5p + 2 = 17
Advertisements
उत्तर
5p + 2 = 17
Putting p = 1 in L.H.S.,
(5 × 1) + 2 = 7 ≠ R.H.S.
Putting p = 2 in L.H.S.,
(5 × 2) + 2 = 10 + 2 = 12 ≠ R.H.S.
Putting p = 3 in L.H.S.,
(5 × 3) + 2 = 17 = R.H.S.
Hence, p = 3 is a solution of the given equation.
APPEARS IN
संबंधित प्रश्न
Complete the last column of the table.
| Equation | Value | Say, whether the Equation is Satisfied. (Yes/No) |
| 5x = 25 | x = -5 |
Check whether the value given in the bracket is a solution to the given equation or not:
4p − 3 = 13 (p = − 4)
Write the given equation in statement form:
3p + 4 = 25
Write a statement for the equation, given below:
12y − 30 = 6
Solve the following equation and verify the answer:
`x/2=x/3+1`
After 16 years, Seema will be three times as old as she is now. Find her present age.
Fill in the blank.
3x − 5 = 7 − x ⇒ x = ______
The shifting of a number from one side of an equation to other is called transposition
A rectangular box has height h cm. Its length is 5 times the height and breadth is 10 cm less than the length. Express the length and the breadth of the box in terms of the height.
Complete the table and by inspection of the table, find the solution to the equation 5t = 35.
|
t |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
______ |
|
5t |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
