Advertisements
Advertisements
प्रश्न
Solve the following equation by trial and error method:
5p + 2 = 17
Advertisements
उत्तर
5p + 2 = 17
Putting p = 1 in L.H.S.,
(5 × 1) + 2 = 7 ≠ R.H.S.
Putting p = 2 in L.H.S.,
(5 × 2) + 2 = 10 + 2 = 12 ≠ R.H.S.
Putting p = 3 in L.H.S.,
(5 × 3) + 2 = 17 = R.H.S.
Hence, p = 3 is a solution of the given equation.
संबंधित प्रश्न
Check whether the value given in the bracket is a solution to the given equation or not:
7n + 5 = 19 (n = 2)
Write the given equation in statement form:
`p/2` + 2 = 8
Simplify:
a − [2b − {3a − (2b − 3c)}]
Simplify:
86 − [15x − 7(6x − 9) −2{10x − 5(2 − 3x)}]
Simplify:
xy − [yz − zx − {yx − (3y − xz) − (xy − zy)}]
Write the following statement as an equation:
A number divided by 8 gives 7.
If x = 1, y = 2 and z = 3, find the value of x2 + y2 + 2xyz.
When a number is divided by 8, the result is –3. The number is ______.
The variable used in the equation 2p + 8 = 18 is ______.
t minutes are equal to 60t seconds.
