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Solve the following differential equation: dd[x+ycos(yx)]dx=xcos(yx)dy - Mathematics

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प्रश्न

Solve the following differential equation:

`[x + y cos(y/x)] "d"x = x cos(y/x) "d"y`

योग
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उत्तर

The given equation can be written as

`("d"y)/("d"x) = (x + y cos(y/x))/(x cos y/x)`  ........(1)

This is a homogeneous differential equations.

Put y = vx

`("d"y)/("d"x) = "v" + x "dv"/("d"x)`

1 ⇒ ∴ `"v" + x "dv"/("d"x) = (x + "v"x cos((vx)/x))/(x cos((vx)/x))`

`"v" + x "dv"/("d"x) = (x[1 + "v" cos "v"])/cos "v"`

`x "dv"/("d"x) = (1 + "v" cos "v")/cos"v" - "v"`

`x "dv"/("d"x) = 1/cos"v"`

cos v dv = `("d"x)/x`

On integration we obtain

`int cos"v"  "d"v = int ("d"x)/x`

sin v = log x + log c

`sin(y/x)` = log x + log c

`sin(y/x)` = log |cx|

Which gives the required solution.

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Solution of First Order and First Degree Differential Equations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Ordinary Differential Equations - Exercise 10.6 [पृष्ठ १६५]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 10 Ordinary Differential Equations
Exercise 10.6 | Q 1 | पृष्ठ १६५

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