Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
If y = ex + c – c3 then its differential equation is
विकल्प
`y = x ("d"y)/("d"x) + ("d"y)/("d"x) - (("d"y)/("d'x))^3`
`y + (("d"y)/("d"x))^3 = x ("d"y)/("d"x) - ("d"y)/("d"x)`
`("d"y)/("d"x) + y = (("d"y)/("d"x))^3 - x ("d"y)/("d"x)`
`("d"^3y)/("d"x^3) = 0`
Advertisements
उत्तर
`y = x ("d"y)/("d"x) + ("d"y)/("d"x) - (("d"y)/("d'x))^3`
APPEARS IN
संबंधित प्रश्न
Solve the following differential equation:
`y"d"x + (1 + x^2)tan^-1x "d"y`= 0
Solve the following differential equation:
`(1 + 3"e"^(y/x))"d"y + 3"e"^(y/x)(1 - y/x)"d"x` = 0, given that y = 0 when x = 1
Choose the correct alternative:
The solution of the differential equation `("d"y)/("d"x) = y/x + (∅(y/x))/(∅(y/x))` is
Solve: `y(1 - x) - x ("d"y)/("d"x)` = 0
Solve: ydx – xdy = 0 dy
Solve: `log(("d"y)/("d"x))` = ax + by
Solve the following homogeneous differential equation:
`x ("d"y)/("d"x) - y = sqrt(x^2 + y^2)`
Solve the following:
`x ("d"y)/("d"x) + 2y = x^4`
Choose the correct alternative:
The variable separable form of `("d"y)/("d"x) = (y(x - y))/(x(x + y))` by taking y = vx and `("d"y)/("d"x) = "v" + x "dv"/("d"x)` is
Solve (x2 + y2) dx + 2xy dy = 0
