Advertisements
Advertisements
प्रश्न
Solve for x:
`sqrt((8^0 + 2/3)` = (0.6)2-3x
Advertisements
उत्तर
`sqrt((8^0 + 2/3)` = (0.6)2-3x
⇒ `(1 + 2/3)^(1/2) = (6/10)^(2-3x)`
⇒ `(5/3)^(1/2) = (3/5)^(2-3x)`
⇒ `(3/5)^(-1/2) = (3/5)^(2-3x)`
⇒ `-(1)/(2)` = 2 - 3x
⇒ -1 = 4 - 6x
⇒ -5 = -6x
⇒ x = `(5)/(6)`.
APPEARS IN
संबंधित प्रश्न
Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`
If 3x + 1 = 9x - 3 , find the value of 21 + x.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
Solve for x:
3 x 7x = 7 x 3x
Solve for x:
1 = px
Solve for x:
p3 x p-2 = px
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
