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प्रश्न
Solve the following equation: `"m"/"n" "x"^2 + "n"/"m" = 1- 2"x"`
योग
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उत्तर
`"m"/"n" "x"^2 + "n"/"m" = 1- 2"x"`
Multiply by mn
m2x2 + n2 = mn - 2mnx
(mx+ n)2 = mn
mx + n =± `sqrt "mn"`
mx = - n ± `sqrt "mn"`
x = `(-"n" ± sqrt "mn")/"m"`
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