Advertisements
Advertisements
प्रश्न
Solve for x: `(x-3)/(x-4)+(x-5)/(x-6)=10/3; x!=4,6`
Advertisements
उत्तर
Solution:
`(x-3)/(x-4)+(x-5)/(x-6)=10/3`
`[(x-3)(x-6)+(x-5)(x-4)]/((x-4)(x-6))=10/3`
`(x^2-9x+18+x^2-9x+20)/((x-4)(x-6))=10/3`
`(2x^2-18x+38)/((x-4)(x-6))=10/3`
`(2(x62-9x+19))/x=10/3(x^2-10x+24)`
`(x-9x+19)/1=5/3[x^2-10x+24]`
`3x^2-27x+57=5x^2-50x+120`
`2x^2-23x+63=0`
`x=7 or x=9/2`
APPEARS IN
संबंधित प्रश्न
The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed per hour in each direction?
Ashu is x years old while his mother Mrs Veena is x2 years old. Five years hence Mrs Veena will be three times old as Ashu. Find their present ages.
The difference of two natural numbers is 5 and the difference of heir reciprocals is `5/14`Find the numbers
Solve the following quadratic equations by factorization: \[\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 4 - \frac{2x + 3}{x - 2}; x \neq 1, - 2, 2\]
Show that x = −3 is a solution of x2 + 6x + 9 = 0.
If the sum of the roots of the equation x2 − x = λ(2x − 1) is zero, then λ =
In each of the following determine whether the given values are solutions of the equation or not.
x2 + x + 1 = 0; x = 1, x = -1.
Solve the following equation by factorization
3x2= x + 4
Find two consecutive odd integers such that the sum of their squares is 394.
Solve the following equation by factorisation :
x2 + 6x – 16 = 0
