Advertisements
Advertisements
प्रश्न
Solve the following determinant equation:
\[\begin{vmatrix}15 - 2x & 11 - 3x & 7 - x \\ 11 & 17 & 14 \\ 10 & 16 & 13\end{vmatrix} = 0\]
Advertisements
उत्तर
Let Δ `=|(15-2x,11-3x,7-x),(11,17,14),(10,16,13)|=0`
`=>|(15-2x-14+2x,11-3x,7-x),(11-28,17,14),(10-26,16,13)|=0` `["Applying" C_1->C_1-2C_3]`
`=>|(1,11-3x,7-x),(-17,17,14),(-16,16,13)|=0`
`=>|(12-3x,4-2x,7-x),(0,3,14),(0,3,13)|=0` `["Applying" C_1->C_1+C_2 "and" C_2->C_2-C_3]`
\[ \Rightarrow \left( 12 - 3x \right)\left( \left( 3 \times 13 \right) - \left( 3 \times 14 \right) \right) = 0\]
\[ \Rightarrow \left( 12 - 3x \right)\left( - 3 \right) = 0\]
\[ \Rightarrow 12 - 3x = 0\]
\[ \Rightarrow 3x = 12\]
\[ \Rightarrow x = 4\]
`=>|(15-2x-14+2x,11-3x,7-x),(11-28,17,14),(10-26,16,13)|=0` `["Applying" C_1->C_1-2C_3]`
`=>|(1,11-3x,7-x),(-17,17,14),(-16,16,13)|=0`
`=>|(12-3x,4-2x,7-x),(0,3,14),(0,3,13)|=0` `["Applying" C_1->C_1+C_2 "and" C_2->C_2-C_3]`
\[ \Rightarrow \left( 12 - 3x \right)\left( \left( 3 \times 13 \right) - \left( 3 \times 14 \right) \right) = 0\]
\[ \Rightarrow \left( 12 - 3x \right)\left( - 3 \right) = 0\]
\[ \Rightarrow 12 - 3x = 0\]
\[ \Rightarrow 3x = 12\]
\[ \Rightarrow x = 4\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
