Advertisements
Advertisements
प्रश्न
Solve by the method of elimination
`x/10 + y/5` = 14, `x/8 + y/6` = 15
Advertisements
उत्तर
`x/10 + y/5` = 14
L.C.M of 10 and 5 is 10
Multiply by 10
x + 2y = 140 → (1)
`x/8 + y/6` = 15
L.C.M of 8 and 6 is 24
3x + 4y = 360 → (2)
(1) × 2 ⇒ 2x + 4y = 280 → (3)
(2) × 1 ⇒ 3x + 4y = 360 → (2)
(3) – (2) ⇒ – x + 0 = – 80
∴ x = 80
Substitute the value of x = 80 in (1)
x + 2y = 140
80 + 2y = 140
2y = 140 – 80
2y = 60
y = `60/2`
y = 30
∴ The value of x = 80 and y = 30
APPEARS IN
संबंधित प्रश्न
Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
2x - 3y = 7
5x + y= 9
Solve the pair of linear (simultaneous) equations by the method of elimination by substitution:
2x + 3y = 8,
2x = 2 + 3y
Solve the following pair of linear (simultaneous) equation using method of elimination by substitution:
3x + 2y =11
2x - 3y + 10 = 0
Solve the following pairs of linear (simultaneous) equation using method of elimination by substitution:
`x/6 + y/15 = 4`
`x/3 - y/12 = 4 3/4`
Solve the following simultaneous equations by the substitution method:
2x + 3y = 31
5x - 4 = 3y
Solve the following simultaneous equations by the substitution method:
3 - (x + 5) = y + 2
2(x + y) = 10 + 2y
A father's age is three times the age of his child. After 12 years, twice the age of father will be 36 more than thrice the age of his child. Find his present age.
* Question modified
Solve by the method of elimination
x – y = 5, 3x + 2y = 25
Solve by the method of elimination
13x + 11y = 70, 11x + 13y = 74
The monthly income of A and B are in the ratio 3 : 4 and their monthly expenditures are in the ratio 5 : 7. If each saves ₹ 5,000 per month, find the monthly income of each
