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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ९

Solve by the method of elimination x – y = 5, 3x + 2y = 25

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प्रश्न

Solve by the method of elimination

x – y = 5, 3x + 2y = 25

योग
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उत्तर

x – y = 5 → (1)

3x + 2y = 25 → (2)

(1) × 2 ⇒ 2x – 2y = 10 → (3)

(2) × 1 ⇒ 3x + 2y = 25 → (2)

(3) + (2) ⇒ 5x + 0 = 35

x = `35/5`

= 7

Substitute the value of x = 7 in (1)

x – y = 5

7 – y = 5

– y = 5 – 7

– y = – 2

y = 2

∴ The value of x = 7 and y = 2

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Methods of Solving Simultaneous Linear Equations by Elimination Method
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अध्याय 3: Algebra - Exercise 3.12 [पृष्ठ १२८]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 3 Algebra
Exercise 3.12 | Q 1. (ii) | पृष्ठ १२८

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