Advertisements
Advertisements
प्रश्न
Solve : 9x - 7 ≤ 5: 28 + 4x ; x ∈ W.
Advertisements
उत्तर
9x – 1 ≤ 28 + 4x
⇒ 9x – 4x – 7 ≤ 28 + 4x – 4x (Subtracting 4x)
⇒ 5x – 7 ≤ 28
⇒ 5x – 7 + 7 ≤ 28 + 7 (Adding 7)
⇒ 5x ≤ 35
⇒ x ≤ 7 (Dividing by 5)
Required answer = {0, 1, 2, 3, 4, 5, 6, 7}
APPEARS IN
संबंधित प्रश्न
If the replacement set is the set of natural numbers, solve: 3x - 4 > 6
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 2x - 1 > 9
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 3x + 7 < 1
Solve : - 17 < 9y - 8; y ∈ Z.
Solve : `2/3"x" + 8 < 12; "x" ∈ "W"`
Solve the inquation 8 – 2x ≥ x – 5; x ∈ N.
Solve the inequation `("2x" + 1)/3 + 15 ≤ 17;` x ∈ W.
Solve:
4x – 5 > 10 – x, x ∈ {0, 1, 2, 3, 4, 5, 6, 7}.
Solve: 15 – 2(2x – 1) < 15, x ∈ Z.
Solve: `("2x" + 3)/5 > ("4x" - 1)/2`, x ∈ W.
