Advertisements
Advertisements
प्रश्न
Solve the inequation -3 + x < 2, x ∈ N.
Advertisements
उत्तर
-3 + x < 2, x ∈ N.
⇒ x < 2 - (-3)
⇒ x < 2 + 3
⇒ x < 5
∴ x = 1, 2, 3, 4 (∵ x ∈ N)
∴ Solution set = {1, 2, 3, 4}
APPEARS IN
संबंधित प्रश्न
If the replacement set is the set of natural numbers, solve: x + 1 ≤ 7
If the replacement set is the set of natural numbers, solve: 3x - 4 > 6
If the replacement set is the set of natural numbers, solve: 4x + 1 ≥ 17
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 2x - 1 > 9
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 3x + 7 < 1
Solve : - 17 < 9y - 8; y ∈ Z.
Solve: `-5 ("x" + 4) > 30 ; "x" ∈ "Z"`
Solve the inequation 18 – 3 (2x – 5) > 12; x ∈ W.
Solve the inequation `("2x" + 1)/3 + 15 ≤ 17;` x ∈ W.
Solve: `("2x" + 3)/5 > ("4x" - 1)/2`, x ∈ W.
