Question

The figure shows a circular wire loop of radius a and carrying a current i, which is placed in a perpendicular magnetic field B. (a) Consider a small part dl of the wire. Find the force on this part of the wire exerted by the magnetic field. (b) Find the force of compression in the wire.

Answer 1

Given:-

Radius of the circular wire loop = a

Electric current flowing through the loop = i

Perpendicular magnetic field = B

(a) The force exerted by the magnetic field on a small element dl of the wire,
F_dl = i. (dl × B) = idlB

Using Fleming's left-hand rule, we can say that the direction of magnetic force is towards the centre for any small element of length dl of the wire (dl and B are perpendicular to each other).

(b) Suppose some part of wire loop subtends a small angle 2θ at the centre of a circular loop

So,

2Tsinθ = i.(dl × B)

= i.2aθ B (Using length of any arc, l =rθ)

∵ θ is very small, sinθ = θ

2Tθ = i.2aθB

∴ T = iaB