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प्रश्न
Six turns of calvin cycle are required to generate one mole of glucose. Explain.
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उत्तर
During the Calvin cycle, 3 molecules of ATP and 2 molecules of NADPH are required for the reduction of one molecule of CO2. Since glucose is a 6-carbon compound, 6 molecules of carbon dioxide are required to prepare one molecule of glucose. Hence, six turns of the calvin cycle are needed to generate one mole of glucose. Hence a total of 18 ATP and 12 NADPH is required for the synthesis of one molecule of glucose.
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संबंधित प्रश्न
Even though a very few cells in a C4 plant carry out the biosynthetic – Calvin pathway, yet they are highly productive. Can you discuss why?
Calvin cycle occurs in ______.
In calvin cycle, carboxylation of RuBP fixed CO2 in number of PGA molecules
The reaction that is responsible for the primary fixation of CO2 is catalysed by ______.
\[\ce{3CO2 + 9ATP + 6NADPH + Water -> glyceraldehyde 3 – phosphate + 9 ADP + 6 NADP+ + 8 Pi}\]
Analyze the above reaction and answer the following questions:
- How many molecules of ATP and NADPH are required to fix one molecule of CO2?
- Where in the chloroplast does this process occur?
What conditions enable Rubirco to function as an oxygenase? Explain the ensuing process.
Why is the RuBisCo enzyme more appropriately called RUBP Carboxylase-Oxygenase and what important role does it play in photosynthesis?
How may molecules of ATP and NADPH are required for every molecule of CO2 fixed in the Calvin cycle?
