Advertisements
Advertisements
प्रश्न
Simplify the following:
`2 "log" 5 +"log" 8 - (1)/(2) "log" 4`
Advertisements
उत्तर
`2 "log" 5 +"log" 8 - (1)/(2) "log" 4`
= `2 "log" 5 + "log" 2^3 - (1)/(2)"log"2^2`
= `2 "log" 5 + 3 "log" 2 - (1)/(2) xx 2 "log" 2`
= 2 log 5 + 3 log 2 - log 2
= 2 log 5 + 2 log 2
= 2(log 5 + log 2)
= 2 log (5 x 2)
= 2 log 10
= 2 x 1
= 2.
APPEARS IN
संबंधित प्रश्न
If 3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x, find x.
Given 3log x + `1/2`log y = 2, express y in term of x.
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 12
Given: log3 m = x and log3 n = y.
Write down `3^(1 - 2y + 3x)` in terms of m and n.
Express the following in terms of log 2 and log 3: log 36
Express the following in terms of log 5 and/or log 2: log250
Express the following in terms of log 2 and log 3: `"log" root(3)(144)`
Express the following as a single logarithm:
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
Express the following as a single logarithm:
`3"log"(5)/(8) + 2"log"(8)/(15) - (1)/(2)"log"(25)/(81) + 3`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 2.25
