Question

If log 2 = 0.3010 and log 3 = 0.4771 ;  find the value of : log 12

Answer 1

We know that log 2 = 0.3010 and log 3 = 0.4771
log 12
= log 2 x 2 x 3
= log 2 x 2 + log 3           ...[ log_amn = log_am + log_an ]
= log2² + log3
= 2log2 + log 3                ...[ nlog_am = log_amⁿ ]
= 2( 0.3010 ) + 0.4771      ...[ ∵ log 2 = 0.3010 and log3 = 0.4771 ]

= 1.0791