Advertisements
Advertisements
प्रश्न
Simplify:
(s2t + tq2)2 – (2stq)2
Advertisements
उत्तर
We have,
(s2t + tq2)2 – (2stq)2 = (s2t)2 + (tq2)2 + 2 × s2t × tq2 – 4s2t2q2 ...[Using the identity, (a + b)2 = a2 + b2 + 2ab]
= s4t2 + t2q4 + 2s2t2q2 – 4s2t2q2
= s4t2 + t2q4 – 2s2t2q2
APPEARS IN
संबंधित प्रश्न
Simplify the following using the identities: 1.73 × 1.73 − 0.27 × 0.27
Find the following product: (y2 − 4) (y2 − 3)
Find the following product: (3x + 5) (3x + 11)
Find the following product: (3x2 − 4xy) (3x2 − 3xy)
Find the following product: (x2 + 4) (x2 + 9)
Expand the following:
(−p + 2q + 3r)2
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(2x + 3)(2x – 5)(2x – 6)
Simplify: (x – 2y + 3z) (x2 + 4y2 + 9z2 + 2xy + 6yz – 3xz)
Simplify:
(1.5p + 1.2q)2 – (1.5p – 1.2q)2
Expand the following, using suitable identities.
`((2a)/3 + b/3)((2a)/3 - b/3)`
